## General, Organic, and Biological Chemistry: Structures of Life (5th Edition)

a. 101.08 $^o C$ b. 100.16 $^o C$ c. 101.75 $^o C$
a. 1. Calculate the $\Delta T_b$ 1 mole of particles = 0.51 $^o C$ $C_6H_{12}O_6$ is a nonelectrolyte: 1 mole $C_6H_{12}O_6$ = 1 mole particles $$2.12 \space moles \space C_6H_{12}O_6 \times \frac{1 \space mole \space particles}{1 \space mole \space C_6H_{12}O_6} \times \frac{1.86 \space ^o C}{1 \space mole \space particles} = 1.08 \space ^oC$$ 2. The boiling point of water is $100$ $^o C$, calculate the boiling point of the solution. $$T_{solution} = T_{water} + \Delta T_b$$ $$T_{solution} = 100 \space ^oC + 1.08 \space ^o C = 101.08 \space ^o C$$ b. 1. Find the molar mass for this compound: $C_{12}H_{22}O_{11}$ : ( 1.008 $\times$ 22 )+ ( 12.01 $\times$ 12 )+ ( 16.00 $\times$ 11 )= 342.30 g/mol 2. Calculate the $\Delta T_b$ 1 mole of particles = 0.51 $^o C$ $C_{12}H_{22}O_{11}$ is a nonelectrolyte: 1 mole $C_{12}H_{22}O_{11}$ = 1 mole particles $$110. \space g \space C_{12}H_{22}O_{11} \times \frac{1 \space mole C_{12}H_{22}O_{11}}{342.30 \space g \space C_{12}H_{22}O_{11}} \times \frac{1 \space mole \space particles}{1 \space mole \space C_{12}H_{22}O_{11}} \times \frac{0.51 \space ^o C}{1 \space mole \space particles} = 0.164 \space ^oC$$ 3. The boiling point of water is $100$ $^o C$, calculate the boiling point of the solution. $$T_{solution} = T_{water} + \Delta T_f$$ $$T_{solution} = 100 \space ^oC + 0.164 \space ^o C = 100.16 \space ^o C$$ c. 1. Find the molar mass for this compound: $NaNO_3$ : ( 22.99 $\times$ 1 )+ ( 14.01 $\times$ 1 )+ ( 16.00 $\times$ 3 )= 85.00 g/mol 2. Calculate the $\Delta T_b$ 1 mole of particles = 0.51 $^o C$ $NaNO_3$ is an electrolyte that produces 2 ions: 1 mole $NaNO_3$ = 2 moles particles $$146 \space g \space NaNO_3 \times \frac{1 \space mole NaNO_3}{85.00 \space g \space NaNO_3} \times \frac{2 \space mole s \space particles}{1 \space mole \space NaNO_3} \times \frac{0.51 \space ^o C}{1 \space mole \space particles} = 1.75 \space ^oC$$ 3. The boiling point of water is $100$ $^o C$, calculate the boiling point of the solution. $$T_{solution} = T_{water} + \Delta T_f$$ $$T_{solution} = 100 \space ^oC + 1.75 \space ^o C = 101.75 \space ^o C$$