Answer
a. 480. g of NaOH
b. 55.5 g of $CaCl_2$
c. 44.6 g of $NaNO_3$
Work Step by Step
a.
1. Find the conversion factors
- 6.00 M $NaOH$ solution: $$6.00 \space moles \space NaOH = 1 \space L \space solution$$
- Molar mass: $ NaOH $ : ( 22.99 $\times$ 1 )+ ( 1.008 $\times$ 1 )+ ( 16.00 $\times$ 1 )= 40.00 g/mol
2. Calculate the mass in grams:
$$2.00 \space L \space solution \times \frac{6.00 \space moles \space NaOH}{1 \space L \space solution} \times \frac{40.00 \space g \space NaOH}{1 \space mole \space NaOH} = 480. \space g \space NaOH$$
b.
1. Find the conversion factors
- 0.100 M $CaCl_2$ solution: $$0.100 \space mole \space CaCl_2 = 1 \space L \space solution$$
- Molar mass: $ CaCl_2 $ : ( 35.45 $\times$ 2 )+ ( 40.08 $\times$ 1 )= 110.98 g/mol
2. Calculate the mass in grams:
$$5.00 \space L \space solution \times \frac{0.100 \space mole \space CaCl_2}{1 \space L \space solution} \times \frac{110.98 \space g \space CaCl_2}{1 \space mole \space CaCl_2} = 55.5 \space g \space CaCl_2$$
c.
1. Find the conversion factors
- 3.00 M $NaNO_3$ solution: $$3.00 \space moles \space NaNO_3 = 1 \space L \space solution$$
- Molar mass: $ NaNO_3 $ : ( 22.99 $\times$ 1 )+ ( 14.01 $\times$ 1 )+ ( 16.00 $\times$ 3 )= 85.00 g/mol
- 1 L = 1000 mL
2. Calculate the mass in grams:
$$175 \space mL \space solution \times \frac{1 \space L}{1000 \space mL} \times \frac{3.00 \space moles \space NaNO_3}{1 \space L \space solution} \times \frac{85.00 \space g \space NaNO_3}{1 \space mole \space NaNO_3} = 44.6 \space g \space NaNO_3$$
