Answer
a. 0.0250 L of $KCl$ solution
b. 0.833 L of $HCl$ solution
c. 480 mL of $K_2SO_4$ solution
Work Step by Step
a.
1. Find the conversion factor:
- 4.00 M $KCl$ solution: $$4.00 \space moles \space KCl = 1 \space L \space solution$$
2. Calculate the volume in L:
$$0.100 \space moles \space KCl \times \frac{1 \space L \space solution}{4.00 \space moles \space KCl} = 0.0250 \space L \space of \space solution$$
b.
1. Find the conversion factor:
- 6.00 M $HCl$ solution: $$6.00 \space moles \space HCl = 1 \space L \space solution$$
2. Calculate the volume in L:
$$5.00 \space moles \space HCl \times \frac{1 \space L \space solution}{6.00 \space moles \space HCl} = 0.833 \space L \space of \space solution$$
c.
1. Find the conversion factors
- 2.50 M $K_2SO_4$ solution: $$2.50 \space moles \space K_2SO_4 = 1 \space L \space solution$$
- 1 L = 1000 mL
2. Calculate the volume in mL:
$$1.20 \space moles \space K_2SO_4 \times \frac{1 \space L \space solution}{2.50 \space moles \space K_2SO_4} \times \frac{1000 \space mL}{1 \space L}= 480 \space mL \space of \space solution$$
