Answer
a. 12.5 moles of C
b. 46.2 moles of H
c. 1.54 moles of N
Work Step by Step
a. Each $ C_{17}H_{21}NO $ has 17 C atoms, thus:$$ 0.733 \space mole \space C_{17}H_{21}NO \times \frac{ 17 \space moles \ C }{1 \space mole \space C_{17}H_{21}NO } = 12.5 \space moles \space C $$
b. Each $ C_{17}H_{21}NO $ has 21 H atoms, thus:$$ 2.20 \space moles \space C_{17}H_{21}NO \times \frac{ 21 \space moles \ H }{1 \space mole \space C_{17}H_{21}NO } = 46.2 \space moles \space H $$
c. Each $ C_{17}H_{21}NO $ has 1 N atom, thus:$$ 1.54 \space moles \space C_{17}H_{21}NO \times \frac{ 1 \space mole \ N }{1 \space mole \space C_{17}H_{21}NO } = 1.54 \space moles \space N $$
