Answer
a. 1.11 moles of C
b. 0.185 mole of O
c. $1.56 \times 10^{24}$ atoms of H
d. $6.68 \times 10^{23}$ atoms of C
Work Step by Step
a. Each $ C_6H_{14}O $ has 6 C atoms, thus:$$ 0.185 \space mole \space C_6H_{14}O \times \frac{ 6 \space moles \ C }{1 \space mole \space C_6H_{14}O } = 1.11 \space moles \space C $$
b. Each $ C_6H_{14}O $ has 1 O atoms, thus:$$ 0.185 \space mole \space C_6H_{14}O \times \frac{ 1 \space mole \ O }{1 \space mole \space C_6H_{14}O } = 0.185 \space mole \space O $$
c. Each $ C_6H_{14}O $ has 14 H atoms, thus:$$ 0.185 \space mole \space C_6H_{14}O \times \frac{ 14 \space moles \ H }{1 \space mole \space C_6H_{14}O } = 2.59 \space moles \space H $$
$$ 2.59 \space moles \space \times \frac{6.02 \times 10^{23} \space atoms }{1 \space mole} = 1.56 \times 10^{24} \space atoms $$
d.$$ 1.11 \space mole \space \times \frac{6.02 \times 10^{23} \space atoms }{1 \space mole} = 6.68 \times 10^{23} \space atoms $$
