Answer
a.
$$2C_6H_{14}(g)+19O_2(g)⟶12CO_2(g)+14H_2O(l)+energy$$
b.
$$2C_5H_{10}(g)+15O_2(g)⟶10CO_2(g)+10H_2O(l)+energy$$
c.
$$2C_4H_{10}(g)+13O_2(g)⟶8CO_2(g)+10H_2O(l)+energy$$
Work Step by Step
1. Write the chemical equation for the combustion of each alkane.
- They will follow this pattern:
$$Alkane+aO_2(g)⟶bCO_2(g)+cH_2O(l)+energy$$
b = number of carbon on the alkane.
c = number of hydrogens on the alkane divided by 2.
a = b + c/2
a. $$C_6H_{14}(g)+\frac{19}{2}O_2(g)⟶6CO_2(g)+7H_2O(l)+energy$$
$$2C_6H_{14}(g)+19O_2(g)⟶12CO_2(g)+14H_2O(l)+energy$$
b. $$C_5H_{10}(g)+\frac{15}{2}O_2(g)⟶5CO_2(g)+5H_2O(l)+energy$$
$$2C_5H_{10}(g)+15O_2(g)⟶10CO_2(g)+10H_2O(l)+energy$$
c. $$C_4H_{10}(g)+\frac{13}{2}O_2(g)⟶4CO_2(g)+5H_2O(l)+energy$$
$$2C_4H_{10}(g)+13O_2(g)⟶8CO_2(g)+10H_2O(l)+energy$$
