General, Organic, & Biological Chemistry 3rd Edition

Published by McGraw-Hill Education
ISBN 10: 0-07351-124-2
ISBN 13: 978-0-07351-124-5

Chapter 2 - Atoms and the Periodic Table - Problems - Page 68: 2.55

Answer

See the explanation

Work Step by Step

Formulae Protons = Z = 8 Neutrons = A − Z Electrons in neutral atom = Z = 8 Group number of oxygen = 16 (group 16 = chalcogens) Isotope notation: $^A_Z X$ Calculate for each isotope (i) Oxygen-16 Protons = 8 Neutrons = 16 − 8 = 8 Electrons = 8 Group = 16 Symbol:$^{16}_8O$ ​ (ii) Oxygen-17 Protons = 8 Neutrons = 17 − 8 = 9 Electrons = 8 Group = 16 Symbol: $^{17}_8O$ ​ (iii) Oxygen-18 Protons = 8 Neutrons = 18 − 8 = 10 Electrons = 8 Group = 16 Symbol: $^{18}_8O$ ​
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