Answer
Molality of iodine solution is $0.1m$
Work Step by Step
Mass of solute $(I_2)=2.603g$
mass of solvent $(CCl_4)=100.0g =0.01kg$
moles of $I_2=mass/molarmass=2.603/254=0.1moles$
Molality is defined as moles of solute present in 1kg of solvent.
molality $=moles(solute)/mass(solvent)kg=0.01/0.1=0.1m$
Molality of iodine solution is $0.1m$
