General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 16 Colligative Properties of Solutions - Problems - Page 594: 1

Answer

Mole fraction of ethanol: $0.089$ Mole fraction of water: $0.911$

Work Step by Step

For Ethanol ( C2H5OH) : $mass=20g$ $molarmass=2\times12.011+5\times1.008+15.99+1.008$ $molarmass=46.069gram/mole$ number of moles of ethanol = Given mass ÷ molar mass. $n_1=20\div46.069$ $n_1=0.434$ For water : $mass=80g$ $molarmass=2\times1.008+15.99$ $molarmass=18.01gram/mole$ number of moles of ethanol = Given mass ÷ molar mass. $n_2=80\div18.01$ $n_2=4.44$ Mole fraction of any substance is defined as ratio of moles of that substance to the sum of moles of all substances. Mole fraction of ethanol: Mole fraction of ethanol = moles of ethanol ÷ ( moles of ethanol + moles of water) mole fraction of ethanol = 0.434 ÷ (0.434 + 4.44) mole fraction of ethanol $=0.089$ Mole fraction of water= $1-$ mole fraction of ethanol Mole fraction of water= $1-0.089$ Mole fraction of water$=0.911$
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