General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 15 Liquids and Solids - Problems - Page 562: 5

Answer

Heat removed $=418.136\text{ J}$

Work Step by Step

Mass of Ga $=5\text{ g}$ Moles of Ga $=mass/molarmass$ Moles of Ga $=5/69.732=0.071712\text{ moles}$ Heat removed $=mass\times specific$-$heat\times temperature$-$change + moles\times heat$-$fusion$ Heat removed $= 5\times0.374\times(29.76-20.00)+0.071712\times5.576\times1000$ $=418.136\text{ J}$
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