Answer
$$q_{`vap} = 6.85 \times 10^{3} \ kJ$$
Work Step by Step
$ NH_3 $ : ( 1.008 $\times$ 3 )+ ( 14.01 $\times$ 1 )= 17.03 g/mol
1. Calculate the resulting heat.
$$q_{`vap} = 5.00 \times 10^3 \ g \times \frac{1 \ mol}{ 17.03 \ g} \times \frac{ 23.33 \ kJ}{ 1.00 \ mol \ NH_3 }$$
$$q_{`vap} = 6.85 \times 10^{3} \ kJ$$
