General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 12 Chemical Calculations for Solutions - Problems - Page 415: 7

Answer

8.3 mL

Work Step by Step

We find: $M_{1}V_{1}=M_{2}V_{2}$ $(18.0\,M)V_{1}=(0.30\,M)(500\,mL)$ $\implies V_{1}=\frac{(0.30\,M)(500\,mL)}{18.0\,M}=8.3\,mL$
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