Answer
0.00653 M
Work Step by Step
We find:
$\text{Moles of solute}=300\times10^{-3}\,g\times\frac{1\,mol\,C_{8}H_{10}N_{4}O_{2}}{194.19\,g}=0.001545\,mol$
$\text{Molarity}=\frac{\text{Moles of solute}}{\text{Liters of solution}}=\frac{0.001545\,mol}{(0.946/4)\,L}=0.00653\,M$
