General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 12 Chemical Calculations for Solutions - Problems - Page 414: 2

Answer

14.3 M

Work Step by Step

We find: $\text{Moles of solute}=572\,g\times\frac{1\,mol\,NaOH}{39.997\,g}=14.3\,mol$ $\text{Molarity}=\frac{\text{Moles of solute}}{\text{Liters of solution}}=\frac{14.3\,mol}{1.00\,L}=14.3\,M$
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