Answer
Molecular formula of glucose is $C_{6}H_{12}O_{6}$
Work Step by Step
C : H : O
$\frac{40.0}{12}:\frac{6.67}{1}:\frac{53.3}{6}$
$\frac{3.33}{3.33}:\frac{6.71}{3.33}:\frac{2.22}{2.22}$
$1$ : :$2$ : $1$
Empirical formula is $CH_{2}O$
Molecular mass of empirical formula $= 12 + 2 + 16 = 30\text{ g/mol}$
Molecular formula mass:
$\frac{180.2}{30}\approx 6$
The formula is: $C_{6}H_{12}O_{6}$
