General Chemistry (4th Edition)

Published by University Science Books
ISBN 10: 1891389602
ISBN 13: 978-1-89138-960-3

Chapter 11 Chemical Calculations - Problems - Page 385: 20

Answer

$35.4\text{ g/mol}$ The element is chlorine

Work Step by Step

Molar mass of $HXO_{3}$ = $1.123\text{ g}/0.0133\text{ mol}$ = $84.4\text{ g/mol}$ Value of Atomic mass of $HXO_{3}$ is equal to its molar mass, $84.4$. The atomic mass of X can be taken by subtracting the atomic mass of $X$ and 3 $O$ from above value Atomic mass of $X$ $= 84.4 - (16 \times 3 + 1) = 35.4$ Hence it can be determined that X is chlorine
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