Chapter 6 - Gases - Example 6-8 - Using the Ideal Gas Equation to Calculate a Gas Density - Page 209: Practice Example B

32.0 g/mol

We find: $d=1.00\,g/mL$ $P=745\,mmHg\times \frac{1\,atm}{760\,mmHg}$ $=0.98026\,atm$ $R=0.08206\,L\,atm\,K^{-1}mol^{-1}$ $T=(109+273)\,K=382\,K$ $M=\frac{dRT}{P}$ $=\frac{(1.00\,g/L)(0.08206\,L\,atm\,K^{-1}mol^{-1})(382\,K)}{0.98026\,atm}$ $=32.0\,g/mol$