#### Answer

$3.46\times10^{21}\,Pb\,atoms$

#### Work Step by Step

Mass of Pb= Volume$\times$Density
$=0.105\,cm^{3}\times11.34\,g/cm^{3}$
$=1.1907\,g$
Number of Pb atoms=
$1.1907\,g\times\frac{6.02214\times10^{23}}{207.2\,g}=3.46\times10^{21} $

Chegg costs money, GradeSaver solutions are free!

Published by
Pearson Prentice Hal

ISBN 10:
0132064529

ISBN 13:
978-0-13206-452-1

$3.46\times10^{21}\,Pb\,atoms$

You can help us out by revising, improving and updating this answer.

Update this answerAfter you claim an answer you’ll have **24 hours** to send in a draft. An editor
will review the submission and either publish your submission or provide feedback.