Answer
$3.46\times10^{21}\,Pb\,atoms$
Work Step by Step
Mass of Pb= Volume$\times$Density
$=0.105\,cm^{3}\times11.34\,g/cm^{3}$
$=1.1907\,g$
Number of Pb atoms=
$1.1907\,g\times\frac{6.02214\times10^{23}}{207.2\,g}=3.46\times10^{21} $
General Chemistry: Principles and Modern Applications (10th Edition)
by Petrucci, Ralph H.; Herring, F. Geoffrey; Madura, Jeffry D.; Bissonnette, Carey
Published by
Pearson Prentice Hal
ISBN 10:
0132064529
ISBN 13:
978-0-13206-452-1
Chapter 2 - Atoms and the Atomic Theory - Example 2-9 - Combining Several Factors in a Calculation - Molar Mass, the Avogadro Constant, Percent Abundances - Page 58: Practice Example A
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