Answer
$6.57\times10^{22}\,Pb\,atoms$
Work Step by Step
We find using Avogadro's number and the molar mass that:
$22.6\,g=22.6\,g\times\frac{6.02214\times10^{23}\,Pb\,atoms}{207.2\,g}$
$=6.57\times10^{22}\,Pb\,atoms$
General Chemistry: Principles and Modern Applications (10th Edition)
by Petrucci, Ralph H.; Herring, F. Geoffrey; Madura, Jeffry D.; Bissonnette, Carey
Published by
Pearson Prentice Hal
ISBN 10:
0132064529
ISBN 13:
978-0-13206-452-1
Chapter 2 - Atoms and the Atomic Theory - Example 2-8 - Relating Number of Atoms, Amount in Moles, and Mass in Grams - Page 57: Practice Example B
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