General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 2 - Atoms and the Atomic Theory - Example 2-8 - Relating Number of Atoms, Amount in Moles, and Mass in Grams - Page 57: Practice Example A


248 g

Work Step by Step

Moles of Cu= $\frac{\text{Number of Cu atoms}}{\text{Avogadro number}}$ $=\frac{2.35\times10^{24}\,atoms}{6.022\times10^{23}\,atoms/mol}=3.90\,mol$ Mass of Cu= Moles of Cu$\times$Molar mass of Cu $=3.90\,mol\times63.546\,g/mol$ $=248\,g$
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