General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 1 - Matter: Its Properties and Measurement - Exercises - Units of Measurement: 29

Answer

a) 68.4 in = 174 cm b) 94 ft = 29 m c) 1.42 lb = 644 g d) 248 lb = 112 kg e) 1.85 gal = 7.00 $dm^{3}$ f) 3.72 qt = 3.52 * $10^{3}$ mL

Work Step by Step

a) 1 inch = 2.54 cm. So 68.4 in = 68.4 * 2.54 cm = 173.736 cm. Rounding to 3 significant figures gives 174 cm. b) 1 ft = 0.3048 m. So 94 ft = 94 * 0.3048 m = 28.6512 m. Rounding to 2 significant figures gives 29 m. c) 1 kg = 2.205 lb 1000 g = 2.205 lb 1 lb = 1000 / 2.205 g = 453.5147392 g. So 1.42 lb = 1.42 * 453.5147392 g = 643.9909297 g. Rounding to 3 significant figures gives 644 g. d) 2.205 lb = 1 kg so 1 lb = 1/2.205 kg = 0.4535147392 kg. So 248 lb = 248 * 0.4535147392 kg = 112.4716553 kg. Rounding to 3 significant figures gives 112 kg. e) 1 gal = 3.78541178 L = 3.78541178 $dm^{3}$. So 1.85 gal = 1.85 * 3.78541178 $dm^{3}$ = 7.003011793 $dm^{3}$. Rounding to 3 significant figures gives 7.00 $dm^{3}$ f) 1.057 qt = 1 L 1.057 qt = 1000 mL 1 qt = 1000 / 1.057 mL = 946.0737938 mL So 3.72 qt = 3.72 * 946.0737938 mL = 3519.394513 mL Rounding to 3 signficicant figures gives 3.52 * $10^{3}$ mL
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