General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 1 - Matter: Its Properties and Measurement - Exercises - Units of Measurement: 27

Answer

a) 0.127 L = 127 mL b) 15.8 mL = 1.58 * $10^{-2}$ L c) 981 $cm^{3}$ = 0.981 L d) 2.65 $m^{3}$ = 2.65 * $10^{6}$ $cm^{3}$

Work Step by Step

a) From L to mL is 3 units smaller. So one has to multiply the number in L with 1000 to convert it into mL. 0.127 L = 0.127 * 1000 = 127 mL b) From mL to L is 3 units bigger, So one has to divide the number in L by 1000 to convert it into L. 15.8 mL = 15.8 / 1000 = 0.0158 L = 1.58 * $10^{-2}$ L c) From $cm^{3}$ to $dm^{3}$ is 1 unit bigger. So one has to divide the number in $cm^{3}$ by 1000 to convert it into $dm^{3}$. (Note: do not divide by 1, since the unit is volume). $dm^{3}$ is the same as L. 981 $cm^{3}$ = 981/1000 $dm^{3}$ = 0.981 $dm^{3}$ = 0.981 L d) From $m^{3}$ to $cm^{3}$ is 2 units smaller. So one has to multiply the number in $m^{3}$ by $10^{6}$ to convert it into $cm^{3}$. (Note: do not multiply with 100, since the unit is volume). 2.65 $m^{3}$ = 2.65 * $10^{6}$ $cm^{3}$
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