#### Answer

1100 g

#### Work Step by Step

Mass of the solution= Density$\times$Volume
$=\frac{1.118\,g}{10^{-3}\,L}\times3.50\,L=3913\,g$
Mass percent= $\frac{\text{mass of the solute}}{\text{mass of the solution}}\times100\%$
$\implies \text{mass of sucrose}=\frac{28.0}{100}\times3913\,g$
$=1100\,g$