General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 1 - Matter: Its Properties and Measurement - Exercises - Percent Composition - Page 29: 66


16.6 L

Work Step by Step

Mass percent= $\frac{\text{mass of the solute}}{\text{mass of the solution}}\times100\%$ $\implies \frac{2.25\times10^{3}\,g}{\text{mass of the solution}}\times100\%=12.0\%$ $\implies \text{mass of the solution}=$ $\frac{2.25\times10^{3}\,g}{12.0}\times100=18750\,g$ Volume= $\frac{\text{mass}}{\text{density}}=\frac{18750\,g}{1.131\,g/mL}=16600\,mL$ $=16600\,mL\times\frac{1\,L}{1000\,mL}=16.6\,L$
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