General Chemistry: Principles and Modern Applications (10th Edition)

Published by Pearson Prentice Hal
ISBN 10: 0132064529
ISBN 13: 978-0-13206-452-1

Chapter 1 - Matter: Its Properties and Measurement - Exercises - Density - Page 28: 52


$9950$ g of the solution.

Work Step by Step

$$10.05\% \space by \space mass:\frac{10.05 \space kg \space (sucrose)}{100 \space kg}$$ $$1.00 \space kg \space (sucrose) \times \frac{100 \space kg}{10.05 \space kg \space (sucrose)} = 9.950 \space kg$$ $$m \space (solution) = 9.950 \space kg \times \frac{1000 \space g}{1 \space kg} = 9950 \space g$$
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