## General Chemistry: Principles and Modern Applications (10th Edition)

$9950$ g of the solution.
$$10.05\% \space by \space mass:\frac{10.05 \space kg \space (sucrose)}{100 \space kg}$$ $$1.00 \space kg \space (sucrose) \times \frac{100 \space kg}{10.05 \space kg \space (sucrose)} = 9.950 \space kg$$ $$m \space (solution) = 9.950 \space kg \times \frac{1000 \space g}{1 \space kg} = 9950 \space g$$