#### Answer

$$V = 101 \space mL$$

#### Work Step by Step

$$m_{CCl_4} = 283.2 \space g - 121.3 \space g = 161.9 \space g$$
$$d = \frac{m}{V}$$ $$1.59 \space g/mL = \frac{161.9 \space g}{V} \longrightarrow V = \frac{161.9 \space g}{1.59 \space g/mL}$$ $$V \approx 101 \space mL$$