Answer
Please see the work below.
Work Step by Step
We know that
$E_k=\frac{1}{2}mv^2$
This can be rearranged as
$v=\frac{1}{2}\sqrt{\frac{226.433\frac{Kg.m^2}{s^2}}{\frac{1}{2}\times 1.00lb\times 0.4536\frac{Kg}{lb}}}=31.60\frac{m}{s}$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 6 - Thermochemistry - Questions and Problems - Page 263: 6.97
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