## General Chemistry 10th Edition

We know that $E_k=\frac{1}{2}mv^2$ This can be rearranged as $v=\frac{1}{2}\sqrt{\frac{226.433\frac{Kg.m^2}{s^2}}{\frac{1}{2}\times 1.00lb\times 0.4536\frac{Kg}{lb}}}=31.60\frac{m}{s}$