Answer
$1.54\times 10^3\frac{J}{g}$
Work Step by Step
We know that
$\frac{686}{1lb}\times \frac{252cal}{1Btu}\times \frac{1lb}{0.4536Kg}\times \frac{1Kg}{10^3g}=1.54\times 10^3\frac{J}{g}$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 6 - Thermochemistry - Questions and Problems - Page 263: 6.95
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