General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 5 - The Gaseous State - Questions and Problems - Page 221: 5.96


Please see the work below.

Work Step by Step

We know that $\frac{u_{H_2}}{u_{H_2se}}=(\frac{M_m(H_2Se)}{M_m(H_2)})^{\frac{1}{2}}$ We plug in the known values to obtain: $\frac{u_{H_2}}{u_{H_2Se}}=(\frac{80.976}{2.016})^\frac{1}{2}=6.338$ Hence the ratio of the rates of effusion of $H_2$ and $H_2Se$ is 6.338 to 1.
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