General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 5 - The Gaseous State - Questions and Problems - Page 221: 5.92

Answer

Please see the work below.

Work Step by Step

We know that $u=(\frac{3RT}{M})^{\frac{1}{2}}$ We plug in the known values to obtain: $u=(\frac{3\times 8.31\times 365}{2.016\times 10^{-2}})^{\frac{1}{2}}=2.12\times 10^3\frac{m}{s}$
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