## General Chemistry 10th Edition

Molar mass of N$H_{4}$N$O_{3}$ is 80.05 g.
Step by step: Molar mass of N$H_{4}$N$O_{3}$ is equal the sum of: 2 x AM of N = 4 x 14.0067 = 28.013 g 4 x AM of H = 4 x 1.00794 = 4.032 g 3 x AM of O = 3 x 15.9994 = 47.998 g _______________________________ Molar mass N$H_{4}$N$O_{3}$ = 28.013 g+4.032 g+47.998 g N$H_{4}$N$O_{3}$ = 80.043 g The molar mass N$H_{4}$N$O_{3}$ is 80.043 g, or 80.05 g.