General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 21 - Chemistry of the Main-Group Elements - Questions and Problems - Page 930: 21.89

Answer

Please see the work below.

Work Step by Step

We know that the number of sodium atoms in a $1.00mg$ crystal of sodium is $1\times 10^{-3}g \space Na\times \frac{1 mol\space Na}{22.99g\space Na}\times\frac{6.02\times 10^{23}Na\space atoms}{1 \space mol}=2.618\times 10^{19} Na \space atoms$
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