General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 21 - Chemistry of the Main-Group Elements - Questions and Problems - Page 930: 21.84

Answer

$1.527Kg \space Mn$

Work Step by Step

We can find the mass of $Mn$ as $1\times 10^3g\times \frac{1mol \space Al}{26.98g\space Al}\times \frac{3 mol Mn}{4 mol Al}\times \frac{54.94g\space Mn}{1 mol \space Mn}=1.527\times 10^3\space Mn=1.527Kg \space Mn$
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