General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 20 - Nuclear Chemistry - Questions and Problems - Page 870: 20.90


Please see the work below.

Work Step by Step

We know that $Bi^{209}_{83}+He^{2}_{1}\rightarrow Po^{A}_{84}+n^{1}_{0}$ From the superscripts, we obtain: $209+2=A+1$ so $A=211-1=210$ The required reaction is $Bi^{209}_{83}+He^{2}_{1}\rightarrow Po^{210}_{84}+n^{1}_{0}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.