Answer
$-3.30\times 10^{-9}g$
Work Step by Step
We know that
$\Delta m=\frac{\Delta E}{c^2}$
We plug in the known values to obtain:
$\Delta m=\frac{-297\times 10^{-3}}{3.00\times 10^8}=-3.30\times 10^{-12}Kg=-3.30\times 10^{-9}g$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 20 - Nuclear Chemistry - Questions and Problems - Page 870: 20.80
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