General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 15 - Acids and Bases - Questions and Problems - Page 659: 15.62


$1.19\times 10^{-10}$

Work Step by Step

We know that $H_3O^+=\frac{K_w}{OH^-}$ We plug in the known values to obtain: $H_3O^+=\frac{1.00\times 10^{-14}}{8.4\times 10^{-5}}=1.19\times 10^{-10}$
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