Answer
Please see the work below.
Work Step by Step
We know that
$H_3O^+=\frac{K_w}{OH^-}$
We plug in the known values to obtain:
$H_3O^+=\frac{1.0\times 10^{-14}}{6.4\times 10^{-4}}=1.56\times 10^{-11}M$
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