General Chemistry 10th Edition

Published by Cengage Learning
ISBN 10: 1-28505-137-8
ISBN 13: 978-1-28505-137-6

Chapter 11 - States of Matter; Liquids and Solids - Questions and Problems - Page 479: 11.43


$1.576KJ $

Work Step by Step

We can find the heat absorbed as $2.25g \space C_3H_8O\times \frac{1 mol\space C_3H_8O}{60.09g\space C_3H_8O}\times\frac{42.1KJ}{1 mol\space C_3H_8O}=1.576KJ $
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.