## General Chemistry 10th Edition

$1.576KJ$
We can find the heat absorbed as $2.25g \space C_3H_8O\times \frac{1 mol\space C_3H_8O}{60.09g\space C_3H_8O}\times\frac{42.1KJ}{1 mol\space C_3H_8O}=1.576KJ$