Answer
Please see the work below.
Work Step by Step
We can find the heat of fusion per mole of $I_2$ as follows
$\frac{0.94795KJ}{15.5gI_2}\times \frac{2\times 126.9g\space I_2}{mol \space I_2}=15.52\frac{KJ}{mol\space I_2}$
General Chemistry 10th Edition
by Ebbing, Darrell; Gammon, Steven D.
Published by
Cengage Learning
ISBN 10:
1-28505-137-8
ISBN 13:
978-1-28505-137-6
Chapter 11 - States of Matter; Liquids and Solids - Questions and Problems - Page 479: 11.41
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