Chapter 6 - Electronic Structure of Atoms - Additional Exercises - Page 254: 6.93d

This set is invalid in $m_s$.

*RULES TO REMEMBER: - $n\gt0$ and $l\ge0$ - $l\lt n$ - $|m_l|\leq l$, which also means $m_l\leq l$ - There are only 2 possible values for $m_s$: $\frac{1}{2}$ and $-\frac{1}{2}$. Here $m_s=0$, which is invalid because there are only 2 possible values for $m_s$, and $0$ is not one of them.