Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 5 - Thermochemistry - Exercises - Page 208: 5.79a


$1C_2H_5OH(l) + 3O_2(g) --> 2CO_2(g) + 3H_2O(l)$

Work Step by Step

1. Write the unbalanced equation: $C_2H_5OH(l) + O_2(g) --> CO_2(g) + H_2O(l)$ 2. Balance the number of Carbon moles: $1C_2H_5OH(l) + O_2(g) --> 2CO_2(g) + H_2O(l)$ 3. Fix the number of Hydrogen moles: $1C_2H_5OH(l) + O_2(g) --> 2CO_2(g) + 3H_2O(l)$ 4. Finally, since we can count 7 Oxygen moles in the right side, and we already have one in $C_2H_5OH(l)$, we can put a 3 next to $O_2(g)$ and the equation will be totally balanced $1C_2H_5OH(l) + 3O_2(g) --> 2CO_2(g) + 3H_2O(l)$
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