Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 5 - Thermochemistry - Exercises - Page 204: 5.16a


131 J

Work Step by Step

$1J=1kg\times\frac{m^2}{s^2}$ Convert to $kg\ and\ \frac{m^2}{s^2}$ $5.13oz\times\frac{1lb}{16oz}\times\frac{1kg}{2.205lb}=0.145kg$ $\frac{95.0mi}{1hr}\times\frac{1hr}{60min}\times\frac{1min}{60sec}\times\frac{1.6093km}{1mi}\times{1000m}{1km}=\frac{42.5m}{sec}$ $E_K=\frac{1}{2}mv^2=(\frac{1}{2})\times0.145kg\times(\frac{42.5m}{sec})^2=\frac{131 kg-m^2}{s^2}=131 J$
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