## Chemistry: The Central Science (13th Edition)

Published by Prentice Hall

# Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Additional Exercises - Page 119: 3.105a

#### Answer

1 $C_{2}H_{2}$ + $\frac{5}{2}$ $O_{2}$ --> 2 $C_{}O_{2}$ + 1 $H_{2}O_{}$. or 2 $C_{2}H_{2}$ + 5 $O_{2}$ --> 4 $C_{}O_{2}$ + 2 $H_{2}O_{}$.

#### Work Step by Step

1. Write the mentioned reaction: $C_{2}H_{2}$ + $O_{2}$ --> $C_{}O_{2}$ + $H_{2}O_{}$. 2. Balance the number of Carbon atoms: 1 $C_{2}H_{2}$ + $O_{2}$ --> 2 $C_{}O_{2}$ + $H_{2}O_{}$ 3. The number of Hydrogen atoms in each side is equal, so we don't need to change anything. 4. Balance the number of Oxygen atoms: 1 $C_{2}H_{2}$ + $\frac{5}{2}$ $O_{2}$ --> 2 $C_{}O_{2}$ + 1 $H_{2}O_{}$. 5. If you want to get rid of the fraction, just multiply all the equation by 2. 2 $C_{2}H_{2}$ + 5 $O_{2}$ --> 4 $C_{}O_{2}$ + 2 $H_{2}O_{}$.

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