Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 3 - Chemical Reactions and Reaction Stoichiometry - Additional Exercises - Page 119: 3.90b


Approximately 1.672 $\times$ $10^{21}$ molecules of aspirin.

Work Step by Step

As we found in 3.90a, there are 0.002778 mols of aspirin in one 0.5g tablet. With that information, we can use this formula: Number of molecules = Number of mols $\times$ 6.02 $\times 10^{23}$ Number of molecules = 0.002778 $\times$ 6.02 $\times 10^{23}$ Number of molecules = 0.01672 $\times 10^{23}$ Number of molecules = 1.672 $\times 10^{21}$ molecules.
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