Answer
Coordination number: 5
Oxidation number: +2
Work Step by Step
The ligand $(bipy)_{2}$ and $I$ that surround the central metal atom $Cu$ are 2+1=3. $bipy$ is a bidentate ligand, the coordination number is 5, because 2 $bipy$ are present and 1 $I$ is present $(2×2)+(1)=5$
Let us suppose the oxidation number of $Cu$ is X. To find the oxidation number, we sum the known oxidation numbers and equal it to the charge on the complex.
Also,
$(bipy)_{2}=2×(0)$
The overall charge is 0 on the complex, thus:
$x-1-1=0$
$x-2=0$
$x=+2$
The oxidation number of $Cu$ is +2
