Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 23 - Transition Metals and Coordination Chemistry - Exercises - Page 1033: 23.25b

Answer

Coordination number: $5$ Oxidation number: $+4$

Work Step by Step

The ligands ($O$ and $Cl_{4}$) that surround the central metal atom $Mo$ are 5. Thus, the coordination number is 5. Let us suppose the oxidation number of $Mo$ is X. To find the oxidation number, we sum the known oxidation numbers and equal it to the charge on the complex. $K_{2}$ = $ 2 \times (+1) $ $Cl_{4}$ = $ 4\times (-1) $ $O = -2 $ The overall charge is zero on the complex, thus: $ 2 \times (+1) + X +( - 2)+ 4\times (-1) = 0 $ $+2 + X -2 - 4 =0 $ $ +2 +X -6 = 0$ $X= +6 -2$ $X= +4$
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