Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 2 - Atoms, Molecules, and Ions - Exercises - Page 76: 2.50d


Molecular: C$_{6}$H$_{12}$O$_{6}$ Empirical: C$_{}$H$_{2}$O$_{}$

Work Step by Step

You are told that glucose has 6 carbon atoms, 12 hydrogen atoms and 6 oxygen atoms, therefore the molecular formula must be: C$_{6}$H$_{12}$O$_{6}$ The greatest common factor of 6, 12 and 6 is 6, so you divide the number of atoms of each by six to maintain the same ratio of each element and you get: C$_{1}$H$_{2}$O$_{1}$ or C$_{}$H$_{2}$O$_{}$, the empirical formula.
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