Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 19 - Chemical Thermodynamics - Exercises - Page 848: 19.27b

Answer

True

Work Step by Step

Because $\Delta S_{sys}+\Delta S_{surr}=0$ in a reversible process, if $\Delta S_{sys}$ is positive then $\Delta S_{surr}$ must be negative.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.