## Chemistry: The Central Science (13th Edition)

$\Delta$ S = -15. 9 J/K
$\Delta$ S = $\frac{H_{fus}}{T}$ But since we are given grams of Ga, we expressed this as $\Delta$ S = $\frac{\frac{m}{MM}(H_{fus})}{T}$, to cancel out both grams and mol. $\Delta$ S = $\frac{\frac{60.0 g}{69.723 g/mol}(5.59 kJ/mol)}{(29.8 ^{\circ}C+273.15)}$ $\Delta$ S = -0.0158794 kJ/mol $\frac{(1000J)}{(1 kJ)}$ $\Delta$ S = -15.9 J/K