Chemistry: The Central Science (13th Edition)

Published by Prentice Hall
ISBN 10: 0321910419
ISBN 13: 978-0-32191-041-7

Chapter 19 - Chemical Thermodynamics - Exercises - Page 848: 19.26b


$\Delta$ S = -15. 9 J/K

Work Step by Step

$\Delta$ S = $\frac{H_{fus}}{T}$ But since we are given grams of Ga, we expressed this as $\Delta $ S = $\frac{\frac{m}{MM}(H_{fus})}{T}$, to cancel out both grams and mol. $\Delta $ S = $\frac{\frac{60.0 g}{69.723 g/mol}(5.59 kJ/mol)}{(29.8 ^{\circ}C+273.15)}$ $\Delta $ S = -0.0158794 kJ/mol $\frac{(1000J)}{(1 kJ)}$ $\Delta $ S = -15.9 J/K
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