Answer
Data Given:
[$C_{2}$$H_{5}$$Br_{}$] = 0.0477 M
[O$H^{-}$] = 0.100 M
Rate = 1.7 * $10^{-7}$ M/s
Rate Law = rate = k[$C_{2}$$H_{5}$$Br_{}$][O$H^{-}$] - Both are in the first order so there both m and n exponents are left as 1-----Now you'll need to plug in the data into the rate law equation.
1.7 * $10^{-7}$ M/s = k[0.100 M][0.0477 M]
Then you'd isolate k
$\frac{1.7 * 10^{-7} M/s }{[0.100 M][0.0477 M]}$ = k
Work Step by Step
$3.5639413^{-5}$ $M^{-1}$/$s^{-1}$ = k
